Exercise 1.12 - Print the input one word per line#
Question#
Write a program that prints its input one word per line.
Solution#
/**
*
* Exercise 1.11 - Write a program that prints its input one word per line.
*
* */
//suggesting a newer approach found on internet
//concept is: do nothing if you meet more than 1 blankspaces or tab spaces or newlines or "anti word characters"
#include<stdio.h>
#define CTRL(x) (x & 0x1f)
main()
{
int c;
while((c = getchar()) != EOF && c != CTRL('d') )
{
if(c == ' ' || c == '\t' || c == '\n' || c == '-')
{
putchar('\n');
while((c = getchar()) == ' ' || c == '\t' || c == '\n' || c == '-' )
{
; //do nothing // we could actually skip the braces and just enter ; after closing the while's condition brackets
}
}
putchar(c);
}
}
/*
#include <stdio.h>
#define IN 1
#define OUT 0
/* This program counts the number of lines, characters and words */
int main (int argc, char *argv[]) {
int c,state;
state = IN;
while((c=getchar()) != EOF) {
if(c==' ' || c == '\t')
state=OUT;
else if (state == OUT) {
state=IN;
putchar('\n');
putchar(c);
}
else
putchar(c);
}
}
*/
Explanation#
In this program, we read the one character at a time and check if the character is a space ‘ ‘, we print newline character, ‘n’ thus going to next line in the output, otherwise we simply print the character c.