Exercise 1.15 - Temperature Convertor using function call#
Question#
Rewrite the temperature conversion program of Section 1.2 to use a function for conversion.
Solution#
/**
*
* Exercise 1.15
*
* Temperature Conversion. Floating point, Symbolic Constant. Functions
*
**/
#include < stdio.h >
#define LOWER 0
#define UPPER 300
#define STEP 20
void fahrtocelsius(void);
void celsiustofahr(void);
int main(void) {
int c;
printf("Temperature Conversion Table\n");
printf("1 - Fahrenheit to Celsius Conversion\n");
printf("2 - Celsius to Fahrenheit Conversion\n");
printf("- Enter your Choice\n");
c = getchar();
if (c == '1')
fahrtocelsius();
else if (c == '2')
celsiustofahr();
else
printf("Invalid Choice\n");
return 0;
}
void fahrtocelsius() {
float fahr;
for (fahr = LOWER; fahr <= UPPER; fahr = fahr + STEP)
printf("%3.0f%6.1f\n", fahr, (5.0 / 9.0) * (fahr - 32.0));
}
void celsiustofahr() {
float celsius;
for (celsius = LOWER; celsius <= UPPER; celsius = celsius + STEP)
printf("%3.0f%6.1f\n", celsius, (9.0 * celsius) / 5.0 + 32);
}
Explanation#
In this program we are going to convert a given Fahrenheit temperature to Celsius or Celsius temperature to Fahrenheit temperature using the formula C=(5/9)(F-32 ). We retain most of the program from section 1.4. In addition This program contains functions such as fahrtocelsius and celsiustofhar. The functions fahrtocelsius and celsiustofhar are used to make the program more dynamic by giving choices to the users for conversion between 1 - Fahrenheit to Celsius Conversion 2 - Celsius to Fahrenheit Converion.